3.7 版新增。
Python 开发模式引入默认情况下,启用非常昂贵的额外运行时校验。它不应该比默认更冗余,若代码正确;才发出新警告,当检测到问题时。
可以启用它使用
-X dev
命令行选项或通过设置
PYTHONDEVMODE
环境变量到
1
.
另请参阅 Python debug build .
启用 Python 开发模式类似于以下命令,但有额外效果如下所述:
PYTHONMALLOC=debug PYTHONASYNCIODEBUG=1 python3 -W default -X faulthandler
Python 开发模式的影响:
添加
default
警告过滤
。展示下列警告:
通常,以上警告被过滤由默认 警告过滤 .
It behaves as if the
-W default
command line option is used.
使用
-W error
command line option or set the
PYTHONWARNINGS
环境变量到
error
to treat warnings as errors.
Install debug hooks on memory allocators to check for:
缓冲下溢
缓冲溢出
Memory allocator API violation
Unsafe usage of the GIL
见
PyMem_SetupDebugHooks()
C 函数。
It behaves as if the
PYTHONMALLOC
environment variable is set to
debug
.
To enable the Python Development Mode without installing debug hooks on memory allocators, set the
PYTHONMALLOC
环境变量到
default
.
调用
faulthandler.enable()
at Python startup to install handlers for the
SIGSEGV
,
SIGFPE
,
SIGABRT
,
SIGBUS
and
SIGILL
signals to dump the Python traceback on a crash.
It behaves as if the
-X faulthandler
command line option is used or if the
PYTHONFAULTHANDLER
environment variable is set to
1
.
启用
asyncio debug mode
。例如,
asyncio
checks for coroutines that were not awaited and logs them.
It behaves as if the
PYTHONASYNCIODEBUG
environment variable is set to
1
.
Check the
encoding
and
errors
arguments for string encoding and decoding operations. Examples:
open()
,
str.encode()
and
bytes.decode()
.
By default, for best performance, the errors argument is only checked at the first encoding/decoding error and the encoding argument is sometimes ignored for empty strings.
io.IOBase
destructor logs
close()
异常。
设置
dev_mode
attribute of
sys.flags
to
True
.
The Python Development Mode does not enable the
tracemalloc
module by default, because the overhead cost (to performance and memory) would be too large. Enabling the
tracemalloc
module provides additional information on the origin of some errors. For example,
ResourceWarning
logs the traceback where the resource was allocated, and a buffer overflow error logs the traceback where the memory block was allocated.
The Python Development Mode does not prevent the
-O
command line option from removing
assert
statements nor from setting
__debug__
to
False
.
The Python Development Mode can only be enabled at the Python startup. Its value can be read from
sys.flags.dev_mode
.
3.8 版改变:
io.IOBase
destructor now logs
close()
异常。
3.9 版改变: encoding and errors arguments are now checked for string encoding and decoding operations.
Example of a script counting the number of lines of the text file specified in the command line:
import sys def main(): fp = open(sys.argv[1]) nlines = len(fp.readlines()) print(nlines) # The file is closed implicitly if __name__ == "__main__": main()
The script does not close the file explicitly. By default, Python does not emit any warning. Example using README.txt, which has 269 lines:
$ python3 script.py README.txt 269
Enabling the Python Development Mode displays a
ResourceWarning
警告:
$ python3 -X dev script.py README.txt 269 script.py:10: ResourceWarning: unclosed file <_io.TextIOWrapper name='README.rst' mode='r' encoding='UTF-8'> main() ResourceWarning: Enable tracemalloc to get the object allocation traceback
In addition, enabling
tracemalloc
shows the line where the file was opened:
$ python3 -X dev -X tracemalloc=5 script.py README.rst 269 script.py:10: ResourceWarning: unclosed file <_io.TextIOWrapper name='README.rst' mode='r' encoding='UTF-8'> main() Object allocated at (most recent call last): File "script.py", lineno 10 main() File "script.py", lineno 4 fp = open(sys.argv[1])
The fix is to close explicitly the file. Example using a context manager:
def main(): # Close the file explicitly when exiting the with block with open(sys.argv[1]) as fp: nlines = len(fp.readlines()) print(nlines)
Not closing a resource explicitly can leave a resource open for way longer than expected; it can cause severe issues upon exiting Python. It is bad in CPython, but it is even worse in PyPy. Closing resources explicitly makes an application more deterministic and more reliable.
Script displaying the first line of itself:
import os def main(): fp = open(__file__) firstline = fp.readline() print(firstline.rstrip()) os.close(fp.fileno()) # The file is closed implicitly main()
By default, Python does not emit any warning:
$ python3 script.py import os
The Python Development Mode shows a
ResourceWarning
and logs a “Bad file descriptor” error when finalizing the file object:
$ python3 script.py import os script.py:10: ResourceWarning: unclosed file <_io.TextIOWrapper name='script.py' mode='r' encoding='UTF-8'> main() ResourceWarning: Enable tracemalloc to get the object allocation traceback Exception ignored in: <_io.TextIOWrapper name='script.py' mode='r' encoding='UTF-8'> Traceback (most recent call last): File "script.py", line 10, in <module> main() OSError: [Errno 9] Bad file descriptor
os.close(fp.fileno())
closes the file descriptor. When the file object finalizer tries to close the file descriptor again, it fails with the
Bad
file descriptor
error. A file descriptor must be closed only once. In the worst case scenario, closing it twice can lead to a crash (see
bpo-18748
了解范例)。
The fix is to remove the
os.close(fp.fileno())
line, or open the file with
closefd=False
.